|| ▼ Answer ▼ ||
The orbital period is 31.62 years when the average distance from the sun is 10AU
|| ✪ Step-by-step explanation✪ ||
Given:
The average distance of the planet from the sun is r = 10 AU
To find the orbital period.
According to Kepler's third law,
∞
![r^(3)](https://img.qammunity.org/2023/formulas/mathematics/high-school/bsjn2kvtrjh7qxtzq04tydrpgao9r2ll.png)
![T^(2) =kr^(3)](https://img.qammunity.org/2023/formulas/physics/high-school/ztksnqlvmpgyfjkhg863r654fdu9oh01g0.png)
![T=(3)/(2)](https://img.qammunity.org/2023/formulas/physics/high-school/5zega757c8bm4dbcgku85q5ql3odxik036.png)
Here, the constant k is taken to be 1.
Substituting the values, the orbital speed will be
![T=(10)(3)/(2)](https://img.qammunity.org/2023/formulas/physics/high-school/qwabmeyui2qf2xdi4qtoi32mravdn1q466.png)
![=31.62~years](https://img.qammunity.org/2023/formulas/physics/high-school/bu0n3qp4kyfpx7bpicxzeyq8gggaf40lpg.png)
Final Answer: The orbital period is 31.62 years when the average distance from the sun is 10AU
Hope this helps!
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