Question

(07.02 MC) what is the value of y in the equation 3(3y - 15) = 0?

Answer 1

The value of y is 5.

Explanation:

First, we will distribute 3 on (3y - 15) This means 3(3y) - 3(15) = 0. Now, we will multiply 3 by what is inside the parentheses for each value. This gives us 9y - 45 = 0. After that, we will add 45 to both sides, which leaves us with 9y = 45. Finally, we will divide 45 by 9 to give us the y value, 5. I hope this helped (:

Answer 2

`y = 5`

Explanation:

Given equation:

`3(3y - 15) = 0`

Divide both sides by 3:

`\implies (3(3y - 15))/(3) = (0)/(3)`

`\implies 3y-15 = 0`

Add 15 to both sides:

`\implies 3y-15 +15= 0+15`

`\implies 3y=15`

Divide both sides by 3:

`\implies (3y)/(3)=(15)/(3)`

`\implies y=5`