9514 1404 393
Answer:
(-∞, 2-√7) ∪ (2+√7, ∞)
Explanation:
The factored form of a polynomial is helpful for solving related inequalities. For quadratics with two real zeros, the sign changes at each zero. If the leading coefficient is positive, the sign is positive to for x-values "outside" either zero, and is negative between the zeros.
Your inequality can be written in standard form as ...
x² -4x -3 > 0
x² -4x +4 -7 > 0
(x -2 -√7)(x -2 +√7) > 0 . . . . . factor the difference of squares (x-2)² -7
The zeros are at x=2-√7 and x=2+√7, so the product of these factors will be positive for x < 2-√7 and x > 2+√7. The solution in interval notation is ...
(-∞, 2-√7) ∪ (2+√7, ∞)
_____
Additional comment
We suspect a typo in the problem statement. If it were to read ... > -3, then the zeros would be at 1 and 3, and the solution would be (-∞, 1)∪(3, ∞).