Question

The length of one of the equal sides of an isosceles triangle is 4 cm. If its base is 2 cm, then what is its area?​

Answer 1

A = 1/2bh

b = 2cm

h will be found using the side of the triangle with Pythagoras theorem

h² + 1² = 4²

h² = 15

h = √15 cm

then,

A = 2*√15

2

A = √15cm²