What is the value of b^2 when the expression is 1/2 (h) (b^1+b^2)

asked Oct 14, 2022 37.2k views

1 vote

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1 vote

Explanation:

Solve for b^2.

$(1)/(2) ( {b {}^(1) + {b}^(2) ) }{h} = a$

$(b {}^(1) + {b}^(2) )h = 2a$

$b {}^(1) + {b}^(2) = (2a)/(h)$

${b}^(2) = (2a)/(h) - {b}^(1)$

Aankhen answered Oct 20, 2022

4.7k points

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