Question

Question is based on Fraction

A man intended to distribute a certain amount of money he had, by giving 2/5 to his wife and the remaining amount equally to his three sons. However, he had to give 1/6 of this amount to his brother before he distributed it as intended. He distributed the remaining amount as originally intended.

Q1. The amount a son received was 40000 rupees less than the amount he was to receive originally. Find the amount the man had intially ?​ ​

Answer 1

9514 1404 393

Answer:

12,00,000 rupees

Explanation:

The fraction originally intended for each son was ...

(1/3)(1 -2/5) = 1/3(3/5) = 1/5

The fraction each son actually received was ...

(1 -1/6)(1/5) = (5/6)(1/5) = 1/6

The difference in these amounts as a fraction of the original distribution is ...

1/5 - 1/6 = (6/30) -(5/30) = 1/30

Then the original distribution is 30 times this difference:

30×40000 rupees = 12,00,000 rupees

_____

Additional comment

Originally-intended distribution (rupees):

• wife: 4,80,000
• each son: 2,40,000

Actual distribution:

• brother: 2,00,000
• wife: 4,00,000
• each son: 2,00,000

1,00,000 = 1 lakh