Question

`f(x) = 1 - 2 x ^(2)`

`g(x) = x + 1`
Compute f(g(-1)).​

Answer 1

Explanation:

f(g(x))= f(x+1)

f(g(1))= f(-1+1)= f(0)

f(0)= 1 - 2(0)²

=1-0

=1