Answer:
Assuming the speed of the plane is 39.6 m/s
vy = 39.6 * sin 30 = 19.8 vertical speed
vx = 39.6 * cos 30 = 34.3 m/s
S = vy t - 1/2 a t^2 to calclulate vertical height
-287 = 19.8 t - 4.9 t^2
4.9 t^2 -19.8 t - 287 = 0
I get t = 9.93 for solving the quadratic for time for ball to hit ground
Horizontal distance = 34.3 m/s * 9.93 s = 341 m
With a vertical speed of 19.9 m/s it takes 19.8 / 9.8 = 2.02 s to reach max height
You can again solve a quadratic or use 19.8 / 2 * 2.02 for time to reach vertical height H = 287 + 20 = 307 m
As a check 307 = 1/2 g t^2 = 4.9 * (9/93 - 2/02)^2 = 307 m max height
After you know how long the ball is in the air there are several ways to calculate the other values.