Question

Help me solve this PLS

Answer 1

Ok so what you have to do to is basically apply Pythagoras Theorem

Explanation:

The hypotenuse squared is equal to the sum of the squares of the legs of a right-angle triangle.

`c^2 = a^2 + b ^2`

Assuming:

c = 10
`\rightarrow` hypotenuse

a = 6.84
`\rightarrow` adjacent leg (base of the triangle)

b = ?
`\rightarrow` opposite leg (height of triangle)

`10^2 = 6.84^2 + b^2`

`b^2 = 10^2 - 6.84^2`

`b = √((10)^2-(6.84)^2)`

`b = 7.295`

With that, you can calculate the area of the triangle:

`A_(triangle) = (a*b)/(2)`

`A_(triangle) = (6.84*7.295)/(2)`

`A_(triangle) = 24.95`

And as your polygon has 9 sides, you can assume that you have 9 of this triangles, so the total area would be:

`A = 9*24.95`

`A = 224.55`

And rounding this result to the nearest hundreth:

`A = 220`