Answer:
(11, 2 )
Explanation:
3y + 2x = 28 → (1)
x = 5y + 1 → (2)
substitute x = 5y + 1 into (1)
3y + 2(5y + 1) = 28 ← distribute parenthesis on left side and simplify
3y + 10y + 2 = 28
13y + 2 = 28 ( subtract 2 from both sides )
13y = 26 ( divide both sides by 13 )
y = 2
substitute y = 2 into (2)
x = 5(2) + 1 = 10 + 1 = 11
solution is (11, 2 )