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v varies directly as the square of x and inversely as the cube of y. Find v when x=3 and y=2, given that v=2 when x=4 and y=3

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Explanation:

If two objects vary directly, we just divide those two objects.

If two objects vary indirectly, we multiply them.

So here we have


\frac{v}{ {x}^(2) } {y}^(3) = k

where k is a constant.

So let analyze when all variables Except k is given.


(2)/(16) (27) = 3.375

So k=3.375


\frac{v}{ {3}^(2) } (2 {}^(3) ) = 3.375


(v)/(9) (8) = 3.375


(v)/(9) (8) = (27)/(8)


v8 = (243)/(8)


v = (243)/(64)


3.796875

User Gerwald
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