Question

WHOEVER GETS THIS RIGHT WILL HAVE 60+ POINTS (MATH) NO BAD ANSWERS ORELSE REPORTING

Answer 1

Part A) The system of equations is

`2x+y=10`

`2x+3y=22`

Part B) The number of minutes it takes you to jog around the park is
`6` mins

Step-by-step explanation:

Part A) Write a system of linear equations

Let
`x` ----> the number of minutes it takes you to jog around the block

Let
`y` ----> the number of minutes it takes you to jog around the park

we know that
`2x+y=10` ----> equation A

and
`2x+3y=22` ----> equation B

Part B) How long does it take you to jog around the park?

Multiply equation A by
`-1` both sides

`-1(2x+y)=-10` ---->
`-2x-y=-10` ----> equation C

Adds equation B and equation C

`2x+3y=22`

`-2x-y=-10`

____________

`3y-y=22-10`

`2y=12`

`y=6` minutes

Find the value of
`x`

`2x+(6)=10`

`2x=10-6`

`x=4/2=2` minutes

Credit:

(This answer was originally made by calculista. All credit goes to them.)

Answer 2

9514 1404 393

Answer:

a. 2x +y = 10; 2x +3y = 22

b. 6 minutes

Step-by-step explanation:

a) The problem statement tells you that ...

x = minutes around the block

y = minutes around the park

2x +y = 10 . . . . twice around the block and once around the park: 10 min

2x +3y = 22 . . . twice around the block and 3 times around the park: 22 min

__

b) Subtracting the first equation from the second gives ...

(2x +3y) -(2x +y) = (22) -(10)

2y = 12 . . . . . . . . simplify

y = 6 . . . . . . . . . divide by 2

It takes you 6 minutes to jog around the park.