Question

What is the equation of the line that passes through the points (4, 15) and (0, 3)?

Answer 1

The equation of the line is y=3x+3

Explanation:

y=mx+b is the y intercept form of the equation of this line.

m=slope, and we find the slope by the equation m=y2-y1/x2-x1. Plugging our number into that formula, we get m=3 - 15/ 0 - 4, or -12/-4, which simplifies to 3.

Now we can add our slope into the formula.

y=3x+b

Next, we solve for the y intercept, or b. You can use whatever point to get the answer, but I will use 4 ,15).

y=mx+b is the equation, or substituting the numbers, gets you 15=3×4+b. now solve for b: b=15-(3)(4). b=3.

now, with slope and y intercept plugged in, the final equation is. y=3x+3

Answer 2

Y=3x+3

Explanation:

Gradient = :
`(y2-y1)/(x2-x1)` = :
`(3-15)/(0-4)` = :
`(-12)/(-4)` = 3

Y= mx + c

y = 3x + c

Insert x and y values for first point(4,15)

15 = 3 (4) + c

15 = 12 + c

3 = c

Y=3x +3