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E=hv h= 6.62 x 10^-34 m^2 kg/ s

What would be the energy contained in a photon of light that has a frequency of 5.0 x 10^12?

Please show work!!

User Bwinton
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1 Answer

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v=5.0×10^12Hz


\\ \sf\longmapsto E=hv


\\ \sf\longmapsto E=6.626* 10^(-34)Js* 5* 10^12s^(-1)


\\ \sf\longmapsto E=33.13* 10^(-22)J

User Todd Vance
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