Question

Find two consecutive even integers such that 4 times the smaller integer is 44 less than 7 times the larger integer

Answer 1

let x be the smaller number.

let x + 2 be the larger number.

4 times the smaller number is 2 more than 3 times the larger number.

in equation form, this becomes:

4x = 3 * (x+2) + 2

simplify this to get:

4x = 3x + 6 + 2 which becomes:

4x = 3x + 8

subtract 3x from both sides of this equation to get:

x = 8

this means that x+2 = 10

the smaller number is 8 and the larger number is 10.

4 times the smaller number is equal to 32.

3 times the larger number + 2 is equal to 32.

requirements of the problem check out ok, so the solution is good.

the smaller number is 8.

the larger number is 10.

Explanation:

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