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(4x^ 2 y^ 3 ).(2xy^ 4 )=

User Gahrae
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2 Answers

4 votes

4x^2 y^3 × 2xy^4 =

4 × 2 × x^2 × x^1 × y^3 × y^4 =

8 × x^(2 + 1) × y^(3 + 4) =

8 × x^3 × y^7 =

8x^3 y^7

User Rraallvv
by
4.4k points
2 votes

ANS

step 1- Equation at the end of step

step 2- Equation at the end of step

step 3- simplify


\\ \frac{ {2}^(2) {x}^(2) {y}^(3) }{ {2xy}^(4) }

step 4- Dividing exponential expressions


\: {x}^(2) divided \: by \: {x}^(1) = {x}^((2 - 1)) = {x}^(1) = x

step 5- Dividing exponential expressions


\: \: {y}^(3) divided \: by \: {y}^(4) = {y}^((3 - 4)) = {y}^( - 1) = \frac{1}{ {y}^(1) } = (1)/(y)

step 6- Dividing exponents


\: {2}^(2) divided \: by \: {2}^(1) = {2}^((2 - 1)) = {2}^(1) = 2

Final result


\\ (2x)/(y)

Thank You !!!

User Ajanth
by
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