80.3k views
0 votes
What is the equation of a line that passes trough (6,-1) and is parallel to the line that has a slope of -2/3?

User DCS
by
7.9k points

1 Answer

3 votes

Answer:

y=-2/3x+3

Explanation:

First, identify the slope you need for your equation. The keyword here is "parallel" so the slope you need is the same as the given slope (-2/3).

Next, use the ordered pair (6,-1); it's on the line that you need to find the equation for. Using slope-intercept form (y=mx+b), plug the -1 in for y, plug the 6 in for x, and plug in your slope of -2/3 for m. Solve for b, your y-intercept. You should get 3.

You have your slope and y-intercept now. Create your equation:

y=-2/3x+3.

User Uliysess
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories