Question

Si la fuerza de repulsión entre dos cargas es 18 × 1013

Answer 1

Step-by-step explanation:

F = kQq/r²

r = √(kQq/F)

a) r = √(8.899(10⁹)(8)(4) / 18(10¹³)) = 0.0397749... m

r = 40 mm

b) r = √(8.899(10⁹)(12)(3) / 18(10¹³)) = 0.0421876... m

r = 42 mm