Question

a ball is rolled at a velocity of 12 miles per second. after 36 seconds, it comes to a stop. what is the acceleration of the ball?

Answer 1

Question :-

• A Ball is Rolled at a Velocity of 12 m/s. After 36 sec , it comes to a stop. What is the Acceleration of the ball ?

Answer :-

• Acceleration is -0.33 m/s² .

Explanation :-

As per the provided information in the given question, we have been given that the Velocity of the ball is 12 m/s . Time is given as 36 sec . And, we have been asked to calculate the Acceleration .

For calculating the Acceleration , we will use the Formula :-

`\bigstar \: \: \boxed{ \sf{ \: Acceleration \: = \: (v \: - \: u)/(t) \: }}`

Where ,

• V denotes to the Final Velocity
• U denotes to the Initial Velocity
• T denotes to the Time Taken

Therefore , by Substituting the given values in the above Formula :-

`\dag \: \: \: \sf { Acceleration \: = \: (Final \: Velocity \: - \: Initial \: Velocity)/(Time) }`

`\longmapsto \: \: \sf { Acceleration \: = \: (0 \: - \: 12)/(36)}`

`\longmapsto \: \: \sf {Acceleration \: = \: ( \: 12 \: )/(36)}`

`\longmapsto \: \: \sf {Acceleration \: = \: ( \: 1 \: )/(3)}`

`\longmapsto \: \bf {Acceleration \: = \: 0.33 \: m/s^(2)}`

Hence :-

• Acceleration of Ball is -0.33 m/s² .

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