Question

Can one of you unhelpful users answer the question without putting links as a d a m n answer?

1. A line goes through the points (1, 6) and (–2, 8). Write the equation of the line in Point-Slope form. Show your work algebraically for full credit.











2. A line goes through the points (1, 6) and (–2, 8). Write the equation of the line in Slope-intercept form. Show your work algebraically for full credit. Hint: this is the same line as in #1.

Answer 1

1)
`y-6=-(2)/(3) (x-1)` and 2)
`y=-(2)/(3) x+(20)/(3)`

Explanation:

Ikr the bots are annoying.

Point-slope form is written as:
`y-y_1=m(x-x_1)`

Slope intercept form is written as:
`y=mx+b`

We also need to find the slope before putting it in this form, which can be done by
`m=(y_2-y_1)/(x_2-x_1)`

1) Points given are (1,6) and (-2,8)

Slope:
`m=(8-6)/(-2-1) =-(2)/(3)`

You can choose either of the two points to put into the formula. I just chose (1,6)

Answer:
`y-6=-(2)/(3) (x-1)`

2) Same points as before and we have the same slope as before. All we need is to find the y intercept which is our b in the equation. You can easily do this by plugging in a point and solving for b. I will choose point (1,6) again.

`6=-(2)/(3) (1)+b`

`6=-(2)/(3) +b`

`6+(2)/(3)=-(2)/(3) +(2)/(3) +b`

`b=6+(2)/(3)=(20)/(3)`

Answer:
`y=-(2)/(3) x+(20)/(3)`