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The points (–7, 7) and (6, –6) fall on a particular line. What is its equation in slope-intercept form?

User Temoncher
by
7.5k points

2 Answers

3 votes

Answer:

y=-x

Explanation:

Slope =1

Substitute m= -1 into the equation:

y= -1x +c

y= -x +c

To find the value of c, substitute a pair of coordinates.

When x= -7, y= 7,

7= -(-7) +c

7= 7 +c

c= 7 -7

c= 0

Thus, the equation of the line is y= -x.

User Beartech
by
8.0k points
5 votes

Answer:

y= -x

Explanation:

Slope-intercept form

y= mx +c, where m is the slope and c is the y-intercept


\boxed{slope = (y1 - y2)/(x1 - x2) }

Slope


= (7 - ( - 6))/( - 7 - 6)


= (7 + 6)/( - 13)


= (13)/( - 13)


= - 1

Substitute m= -1 into the equation:

y= -1x +c

y= -x +c

To find the value of c, substitute a pair of coordinates.

When x= -7, y= 7,

7= -(-7) +c

7= 7 +c

c= 7 -7

c= 0

Thus, the equation of the line is y= -x.

User Saus
by
7.8k points

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