151k views
0 votes
Find the 5th derivative by using calculus with full workings of 7g^8+2g^7+4g^6+3g^5+g^2+5g+276.3

User Arvindch
by
5.5k points

1 Answer

4 votes

This is an exercise in applying the power rule, which says


f(x) = x^n \implies f'(x) = nx^(n-1)

Starting with


7g^8 + 2g^7 + 4g^6 + 3g^5 + g^2 + 5g + 276.3

we have

• first derivative


56g^7 + 14g^6 + 24g^5 + 15g^4 + 2g + 5

• second derivative


392g^6 + 84g^5 + 120g^4 + 60g^3 + 2

• third derivative


2352g^5 + 420g^4 + 480g^3 + 180g^2

• fourth derivative


11760g^4 + 1680g^3 + 1440g^2 + 360g

• fifth derivative


\boxed{47040g^3 + 5040g^2 + 2880g + 360}

User Gauls
by
5.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.