Question

How would you calculate ( 2x + 1 )( x + 6 )( x - 4 ) = 2x^3 + ax^2 + bx -24

Answer 1

(2x+1)(x+6)(x-4)= 2x³+ax²+bx-24

(2x²+x+12x+6)(x-4) = 2x³+ax²+bx-24

2x³+x²+12x²+6x-8x²-4x-48x-24 = 2x³+ax²+bx-24

2x³+x²+12x²+6x-8x²-4x-48x-24- 2x³-ax²+bx-24=0

5x²-46x-ax²+bx-48=0

-ax²+5x²+bx-46x-48=0