Question

What is an equation for the line perpendicular to y=-1/8x+6 that passes through (-3,-10)

Answer 1

y = 8x + 14

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = -
`(1)/(8)` x + 6 ← is in slope- intercept form

with slope m = -
`(1)/(8)`

Given a line with slope m then the slope of a line perpendicular to it is

`m_(perpendicular)` = -
`(1)/(m)` = -
`(1)/(-(1)/(8) )` = 8 , then

y = 8x + c ← is the partial equation

To find c substitute (- 3, - 10 ) into the partial equation

- 10 = - 24 + c ⇒ c = - 10 + 24 = 14

y = 8x + 14 ← equation of perpendicular line