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Find two numbers with a sum of 104 and a difference of 42

User Yroc
by
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2 Answers

3 votes

Answer:


a=73 \text{ and } b=31

Explanation:


a+b=104 --- (1)\\a-b=42 ---(2)\\

Add (1) and (2), we get


2a=104+42\\a=(146)/(2)\\=73


73-b=42\\-b=42-73\\b=31

User Guiyo
by
8.8k points
2 votes

Answer:

31 and 73

Explanation:

Writing this is variable form,

x+y = 104

x-y = 42

If we use the process of elimination and add the system of equations together;

2x = 146

x = 73

Substituting that back in;

x - y = 42

(73) - y = 42

y = 31

User Anhiqkao
by
8.1k points

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