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If f'(0) = 5 and F(x) = f(3x), what is F'(0)?

User Lebby
by
8.4k points

2 Answers

2 votes

Answer:

F'(0)=15

Explanation:

Differentiate
F(x) with respect to
x.


F'(x)=3f'(x)

Subsitute
0 for
x in the above equation.


F'(0)=3f'(0)\\=3\cdot5\\=15

User Brownmike
by
8.4k points
1 vote

Answer:


\displaystyle F'(0) = 15

Explanation:

We are given that:


f'(0) = 5 \text{ and } F(x) = f(3x)

And we want to find F'(0).

First, find F(x):


\displaystyle F'(x) = (d)/(dx)\left[ f(3x)]

From the chain rule:


\displaystyle \begin{aligned} F'(x) &= f'(3x) \cdot (d)/(dx) \left[ 3x\right] \\ \\ &= 3f'(3x)\end{aligned}

Then:


\displaystyle \begin{aligned} F'(0) & = 3f'(3(0)) \\ \\ & = 3f'(0) \\ \\ & = 3(5) \\ \\ & = 15\end{aligned}

In conclusion, F'(0) = 15.

User DiegoS
by
8.5k points

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