Question

Can someone please help me do this

Answer 1

Explanation:

CD is Pole

∠CAD = 4° {Alternate interior angles}

ΔCAD,

`(opposite \ side)/(adjacent \ side)= tan 4\\\\ (90)/(AD)=tan \ 4\\\\ (90)/(AD) = 0.069\\\\90 = 0.069*AD\\\\ (90)/(0.069)=AD\\\\AD = 1304 \ ft`

In ΔCDB,

∠B = 5° {Alternate interior angles}

`Tan \ 5 = (90)/(BD)\\\\0.09* BD = 90\\\\BD = (90)/(0.09)\\\\BD = 1000 \ ft`