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A spelunker explores a new underground cave. He descends into the cave at a rate of 4 feet per minute. What is the change in position of the spelunker after 50 minutes?

User Gmetax
by
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1 Answer

2 votes

Answer:

4 * 50 = 200

Explanation:

Because he is descending at a rate of 4 feet every minute, after 50 minutes he is 200 feet down.

User Minx
by
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