6k^3+10k^2−56k and 5(7k−3)(3k−7)share a common binomial factor. What binomial factor do they share?

asked Sep 6, 2022 85.9k views

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2 votes

Answer:

Explanation:

$6k^3+10k^2-56k\\2k(3k^2+5k-28)\\=2k[3k^2+12k-7k-28]\\=2k[3k(k+4)-7(k+4)]\\=2k(k+4)(3k-7)$

common factor is 3k-7

Ahmad Vatani answered Sep 12, 2022

4.4k points

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