Question

An object moves according to the distance (s) in feet, time (tin seconds equation:

s(t) = - 4t ^ 2 + 237t + 744
Find the time to reach maximum height . Find the maximum height .

Answer 1

Explanation:

The max is a point with coordinates (-b/2a, s(-b/2a))

s(t) = - 4t ² + 237t + 744

-b/2a = -237 /2*(-4)= 237 / 8 ≈29.625

s(237/8) = -4(237/8)² +237*237/8 +744

= -(237²/ 16 ) +(237²/8 ) +744

≈4254.563

The time when the maximum height is reached is t ≈ 29.625 seconds

The maximum hight is at s(t) ≅4,254.563 feet