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A rectangle is three times as long as it is wide.if its perimeter is 56cm .find the width of the perimeter ​

2 Answers

5 votes

Answer:

width = 7 cm

Explanation:

let w be width then length = 3w

The opposite sides of a rectangle are congruent , then perimeter is

2w + 2(3w) = 56 , that is

2w + 6w = 56

8w = 56 ( divide both sides by 8 )

w = 7

That is width of rectangle is 7 cm

User Srinivasan JV
by
5.4k points
3 votes

❆ Cᴏɴᴄᴇᴘᴛ :-

In this question, we will take the help of the branch of mathematics known as "Perimeter and area". We will also use "linear equation in one variable". Let's solve it!


\sf \dag \: \red{Given :-}

  • Perimeter of a rectangle = 56 cm

Let the width be x

Therefore, the length will be 3x.


\sf \pink{Formula \: used :-}


\boxed{ \red \bigstar \: { \sf \orange{perimeter \: of \: a \: rectangle \: = 2(length + breadth)}}}

Now we will simply put the given values in the formula to get the required answer.


\sf \longrightarrow \: 56 \: cm = 2(x + 3x) \\ \sf \longrightarrow \: 56 \: cm = 2x + 6x \: \: \: \\ \sf \longrightarrow \: 8x = 56 \: cm \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf \longrightarrow \: x = (56 \: cm)/(8) = 7 cm


\sf \green{ \therefore \: width \: = x = 7 \: cm \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:} \\ \sf \green{ and \: length \: = 3x = 3 * 7 = 21 \: cm}

I hope that helps :))

User Eze
by
5.1k points
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