Question

Find 3 consecutive even integers such
that the sum of the first and third is -16.

Answer 1

1st number = -10

2nd number = -8

3rd number = -6

Explanation:

Take the first number as x

The next consecutive even number will be x+2

The 3rd even number will be x+4.

Sum of 1st and 3rd number = -16

(x) + (x+4) = -16

x+ x+4 = -16

2x + 4 = -16

2x = -16 -4

2x = -20

x =
`(-20)/(2)`

x = -10

2nd number = x+ 2

= -10 + 2

= -8

3rd number = x + 4

= -10 + 4

= -6

Hope this helps.