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1 vote
What is the mass of 6.728 x 10^23 atoms Ag?

2 Answers

4 votes

Answer:

1.21*10^2 g

Step-by-step explanation:

6.728*10^23 atom Ag *1 mol/6.022*10^23 (Avogadro's number)*107.868 g (Ag atomic mass)/1 mol = 120.514099 g > (rounded and scientific notation) 1.21*10^2 g

Hope this helps! If you have any questions about this answer, feel free to put them in the comments.

User Timothy Swan
by
4.8k points
3 votes

Answer: 18.02 g

Step-by-step explanation:

im pretty sure thats the anwser but im not 100% sure if it correct

User Shivansh Potdar
by
4.6k points