Question

Solve 12x^2+5x-4=12^2x+6

Answer 1

x = 2, x = -5

Explanation:

`{12}^{ {x}^(2) + 5x - 4 } = {12}^(2x + 6) \\ (Bases\: are\: equal\: so\: exponents\: \\will\:also\:be \: equal) \\ \implies \: {x}^(2) + 5x - 4 = 2x + 6 \\ \\ \implies \: {x}^(2) + 5x - 4 - 2x - 6 = 0\\ \\ \implies \: {x}^(2) + 5x - 2x - 4- 6 = 0\\ \\ \implies \: {x}^(2) + 5x - 2x - 10 = 0\\ \\ \implies \:x(x + 5) - 2(x + 5) = 0\\ \\ \implies \:(x + 5)(x - 2) = 0 \\ \\ \implies \:x + 5 = 0 \: \: or \: \: x - 2 = 0 \\ \\ \implies \:x = - 5 \: \: or \: \: x = 2`

Answer 2

okay so we need to solve for x.

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FIRST STEP: 12x^2+5x-4=12^2x+6 would turn into x2 + 5x - 4 = 2x + 6 so it'd have equal bases.

SECOND STEP: move any number with "x" in it to the left side. it ends up as x2 + 3x - 4 = 6

THEN, we use the AC method to eliminate any unnecessary numbers.

you should end up with ( x - 2) (x + 5) = 0

SO, the answer is your third option. ( x = 2, x = -5)

Explanation: