Question

3x^2 +x-4=0 give your answers to two decimal places quadratic equation

Answer 1

Answer: 3x² + 2x - 4 = 0

Step by step explanation: Δ = b² - 4.a.c

Δ = 2² - 4 . 3 . -4

Δ = 4 - 4. 3 . -4

Δ = 52

x = (-b +- √Δ)/2a

x' = (-2 + √52)/2.3

x'' = (-2 - √52)/2.3

x' = 0,8685170918213297

x'' = -1,5351837584879966

2 Decimal places

x' = 0,87

x'' = -1,54