Question

What is an equation of the line that passes through the point (8,-4) and is parallel to the line x-4y=12?

Answer 1

Explanation:

x - 4y = 12

x - 12 = 4y

y = (1/4)x - 3

the slope of this line is the factor of x : 1/4

the parallel line has the same slope, of course.

so, its line function is

y = (1/4)x + c

c is the y-intercept. and we get it by using the provided point coordinates :

-4 = (1/4)×8 + c

-4 = 2 + c

c = -6

so, the equation of the parallel line is

y = (1/4)x - 6