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What is the slope of a line perpendicular to the line whose equation is 3x-3y=-63
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5 votes
What is the slope of a line perpendicular to the line whose equation is 3x-3y=-63

User Yeongjun Kim
by
7.9k points

1 Answer

5 votes

Answer:

The slope is -x

Explanation:

-3y = -3x -63

y = x + 21

User Kev
by
8.3k points
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