Question

Δjkl has j = 7, k = 11, and m∠j = 18°. Complete the statements to determine all possible measures of angle k. Triangle jkl meets the criteria, which means it is the ambiguous case. Substitute the known values into the law of sines: startfraction sine (18 degrees) over 7 endfraction = startfraction sine (uppercase k) over 11 endfraction. Cross multiply: 11sin(18°) =. Solve for the measure of angle k, and use a calculator to determine the value. Round to the nearest degree: m∠k ≈ °. However, because this is the ambiguous case, the measure of angle k could also be °

Answer 1

JKL meets the SSA ✔️

Cross multiply: 11sin(18*) = 7sin(K) ✔️

Round to the nearest degree: m<k = 29* ✔️

The measure of angle K could also be 151 ✔️

Explanation: Can confirm and just did it

Answer 2

Triangle JKL meets the SSA criteria, which means it is the ambiguous case.

Substitute the known values into the law of sines: StartFraction sine (18 degrees) Over 7 EndFraction = StartFraction sine (uppercase K) Over 11 EndFraction.

Cross multiply: 11sin(18°) = 7sin(K)

.

Solve for the measure of angle K, and use a calculator to determine the value.

Round to the nearest degree: m∠K ≈ 29°.

However, because this is the ambiguous case, the measure of angle K could also be 151°.

Step-by-step explanation:

got it right on edge