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Moira uses a difference quotient to determine the average rate of change of f(x) = x2 + 14x from x = –11 to x = 8.

She shows the following work.

Moira uses a difference quotient to determine the average rate of change of f(x) = x-example-1
Moira uses a difference quotient to determine the average rate of change of f(x) = x-example-1
Moira uses a difference quotient to determine the average rate of change of f(x) = x-example-2
User Freonix
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2 Answers

4 votes

Answer:

D

Explanation:

User Marcus Gomes
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2 votes

9514 1404 393

Answer:

(d) She substituted incorrectly ..

Explanation:

The interval Moira wants to use to find the difference quotient is [-11, 8]. This is the interval [x, x+h], so ...

x = -11

x +h = 8

Then ...

h = 8 -x = 8 -(-11) = 19

The proper substitution would be ...

difference quotient = 2x +14 +h = 2(-11) +14 +19

difference quotient = 11

User Janisa
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