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2.) Use the Slope Intercept Form of a line to find the equation of the line from point C to point D.

Slope Intercept Form of a Line:

y = mx + b

m is the slope and b is the y-intercept

2.) Use the Slope Intercept Form of a line to find the equation of the line from point-example-1
User Yole
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2 Answers

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First we need slope

  • C=(0,0)
  • D(7,12)


\\ \sf\longmapsto m=(12-0)/(7-0)


\\ \sf\longmapsto m=(12)/(7)

Put D co-ordinates on y=mx+b


\\ \sf\longmapsto 12=(12)/(7)(7)+b


\\ \sf\longmapsto 12=12+b


\\ \sf\longmapsto b=12-12


\\ \sf\longmapsto b=0

Now

slope intercept form.


\\ \sf\longmapsto y=(12)/(7)x

  • As b=0
User Adam Parkin
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3 votes

Answer:

• General equation of a line:


{ \rm{y = mx + b}}

Consider end points of line CD: (0, 0) and (7, 12):

• find the slope, m:


{ \rm{slope = (y _(2) - y _(1) )/(x _(2) - x _(1) ) }} \\ \\ { \tt{m = (12 - 0)/(7 - 0) }} \\ \\ { \underline{ \tt{ \: \: m = (12)/(7) \: \: }}}

• using end point (0, 0), find the y-intercept, b:


{ \rm{y = mx + b}} \\ \\ { \rm{0 = ( (12)/(7) * 0) + b}} \\ \\ { \tt{b = 0}}

• therefore, equation of line CD is;


{ \boxed{ \boxed{ \tt{ \: \: y = (12)/(7)x \: \: }}}}

User Dustfinger
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