If 26.5 g of NaOH is added to 0.600 L of 1.00 M Mn(NO₃)₂, how many grams of Mn(OH)₂ will be formed in the following precipitation reaction? 2 NaOH(aq) + Mn(NO₃)₂(aq) → Mn(OH)₂ (s) + 2 NaNO₃(aq)

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asked Dec 13, 2022 216k views

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If 26.5 g of NaOH is added to 0.600 L of 1.00 M Mn(NO₃)₂, how many grams of Mn(OH)₂ will be formed in the following precipitation reaction?

2 NaOH(aq) + Mn(NO₃)₂(aq) → Mn(OH)₂ (s) + 2 NaNO₃(aq)

Advanced Placement (AP)
high-school

Pixelbrackets asked

by Pixelbrackets

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I outlined the numbers 1 and 2 to show the sequence of the solution.

Hope you can understand. All the best!

If 26.5 g of NaOH is added to 0.600 L of 1.00 M Mn(NO₃)₂, how many grams of Mn(OH-example-1

If 26.5 g of NaOH is added to 0.600 L of 1.00 M Mn(NO₃)₂, how many grams of Mn(OH-example-2

Brett H answered Dec 17, 2022

by Brett H

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