Question

This is my last question plz help me.

Answer 1

• 
  `f(x)=27`
• 
  `g(5) = -18`

Explanation:

`f(x)=2x^2 -3x`
`f(-3)`

`g(x)=-3x-3`
`g(5)`

Replace everywhere "x" is with the given function. Then solve:

• 
  `f(-3)`

`f(x)=2x^2 -3x\\\\f(x)=2(-3)^2-3(-3)`

Use PEMDAS

`-3 * -3 = 9`

`f(x)=2(-3)^2-3(-3)\\\\f(x)=2(9)-3(-3)`

`2 * 9 = 18\\3*-3=-9\\18- (-9)=27`

`f(x)=27`

• 
  `g(5)`

`g(x)=-3x-3\\\\g(x)=-3(5)-3\\-3* 5 = -15\\-15-3=-18`

`g(5) = -18`

(Please! MAKE sure to ask me how and why I solved every SINGLE equation. I will answer ASAP! Please feel free to do so :)