Question

Example Compute the capacitance of a parallel-plate capacitor with plates 10cm by 20cm, separation of 5mm, and a mica dielectric.​

Answer 1

Step-by-step explanation:

Mica dielectric constant (k) is approximately 3. The distance between the plates is 5 mm =
`5*10^(-3)` m = d and the area of each plate is
`A = 0.1* 0.2=2* 10^(-2) m^(2)`. So, the capacitance of that capacitor is:

`C=(\epsilon_(0)kA)/(d)=((8.85*10^(-12))(3)(2*10^(-2))/(5*10^(-3))=10.62*10^(-11) =1.062*10^(-10) F`

or approximately 0.106 nF.