Question

1) A race car travels east with a forward velocity of 40 m/s and slows at a constant rate

to 16 m/s over 9 S.

Answer 1

Step-by-step explanation:

• v=u+at
• v=40+16×9
• v=40+144
• v=184 m/s

Answer 2

• initial velocity=u=40m/s
• Time=t=9s
• Acceleration=+16m/s^2

`\\ \sf\longmapsto v=u+at`

`\\ \sf\longmapsto v=40+(16)(9)`

`\\ \sf\longmapsto v=40+144`

`\\ \sf\longmapsto v=184m/s`