Question

What is the solution set of the equation using the quadratic formula?

x^2+2x+10=0

A.) {−1+3i, −1−3i}
B.) {−2+6i, −2−6i}
C.) {2i, −4i}
D.) {−1}

Answer 1

`\frac{ - b \pm \sqrt{ {b}^(2) - 4ac } }{2a} \\ ( - 2 \pm √(4 - 4(1)(10)) )/(2) \\ = ( - 2 \pm √( - 36) )/(2) \\ = ( - 2 \pm 6i )/(2) \\ - 1 \pm3i \\ so \: the \: answer \: is \: A`