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A linear function has a slope of 2 and goes through the point (6,-4)

A linear function has a slope of 2 and goes through the point (6,-4)-example-1
User Sibbo
by
8.4k points

2 Answers

5 votes

Answer:

M = -2, b = 8, y = -2 + 8

Explanation:

points are at (6 , -4)

M is -2

Since the slope is negative the line has to go downward from left to right.

Also the slope tells you that the rise (difference in the y axis) has to be 2 times the run (difference in the x axis).

Use your first point on the line (6, -4) and find where the line will cross the y axis when x is 0 which is b.

Using y = mx + b

y = -2x + b

Plugin x = 6 and y = -4 in the above equation

-4 = -2*6 + b

-4 = -12 + b

-4 + 12 = b

b = 8

So your line crosses the y axis at (0, 8)

You can prove this by plugging in the y value in the same equation

y = mx + b

8 = -2x + 8

8 - 8 = 2x

0 = 2x so x=0

Now you equation can be determine also using y = mx + b. Plug in what you know so far.

M (slope) is -2, b you calculated to be 8 so

y = -2x + 8

User Rafalmp
by
7.5k points
3 votes

Answer:

y = 2x - 16

Explanation:

Slope = m = -2

Y = mx + b

y = -2x + b

Plugin x = 6 and y = -4 in the above equation

-4 = (-2)*6 + b

-4 = -12 + b

-4 + 12 = b

b = 8

Equation : y = -2x + 8

User Xpros
by
8.6k points

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