Question

How do I find the vertex and axis of symmetry

H(x) = (x+4)^2

Answer 1

The axis of symmetry occurs at x=4 and the vertex at y=64

Explanation:

Expand h(x)=x²+8x+16

Axis of symmetry=-b/2a

x=-8/2•1=4

The axis of symmetry is x=4

h(4)=(4)²+8(4)+16

=16+32+16

=64

The vertex occurs at y=64