Question

A golfer hits a golf ball horizontally off an elevator tee. The ball lands in the fairy’s at 280m away. The ball is hit with an initial velocity of 52.7m/s. What is the height above the fairway of the tee?

Answer 1

H = Vy t - 1/2 g t^2 height after time t

H = g t^2 / 2 initial Vy = 0 and take down as positive

t = S / Vx = 280 / 52,7 = 5.31 sec time to travel horizontally

H = g / 2 * 5.31^2 = 138 m height of tee above fairway