Answer:
or
![44 (1)/(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/s2qg80yoj5lbzh42m75ttyryocy7jaqxtb.png)
Explanation:
Given the problem,
![26 + (10 - 2^3)/4 + 3 * 6](https://img.qammunity.org/2022/formulas/mathematics/high-school/714ya0een54lat7axx422byoxw01jmzy2f.png)
Follow the PEMDAS order of operations. Start by working on the terms inside the parenthesis:
![2^3 = 2*2*2 = 8](https://img.qammunity.org/2022/formulas/mathematics/high-school/vvkkq0p141v5dnwsb6jop4maf08us6lk6p.png)
= 26 + (10 - 8) ÷ 4 + 3 × 6
= 26 + (2) ÷ 4 + 3 × 6
Next, divide 2 by 4:
= 26 +
+ 3 × 6
Multiply 3 and 6:
= 26 +
+ 18
Add 26 and
:
=
+ 18
Add
and 18. Convert 18 into fraction:
=
![(53)/(2) + 18 = (53)/(2) + (18*2)/(2) = (18*2+53)/(2) = (89)/(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/35yno7lcwsf2ul836hd4ih8ok0thzf5yek.png)
=
(convert
by dividing 89 by 2 to get
).
Therefore, the correct answer is
or
.