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If df = 9x-39 find ef. de = 47 ef= 3x+10
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If df = 9x-39 find ef. de = 47 ef= 3x+10

User Jeremy Goodell
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1 Answer

6 votes

9514 1404 393

Answer:

EF = 58

Explanation:

We assume point E lies on line segment DF, so that ...

DF = DE +EF

9x -39 = 47 +(3x +10)

6x = 96 . . . . . . . . . . . . . . . subtract (3x-39)

x = 16 . . . . . . . . . . . divide by 6

EF = 3×16 +10 = 58

User Nikola Nastevski
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